Question

For a flow of 5.7 mld ( million litres per day ) and a detention time of 2 hours, the surface area of a rectangular sedimentation tank to remove all particle have settling velocity of 0.33 mm / s is (a) 20 m2 (b) 100 m2 (c) 200 m2 (d) 400 m2

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Settlement within detention period = .00033 *2 hrs = .00033*2*60*60 = 2.376 m.

Flow = 5.7 MLD = 5.7 * 10^6 LD = 5.7*10^3 M3 per Day = (5.7*10^3)/24 m3 per hour = 237.5 m3 per hour.

Flow within detention period = 237.5 *2 m3 = 475 m3.

Area = Flow/settlement = 475/2.376 = 199.91 m2 = 200 m2.