Question

For a freely falling body, the distances travelled in 3rd, 5th and 7th second are in the ratio
3:5:7
O
2:4:6
O
5:9:13
9:25:49​

Answer 1

Answer:

3:5:9

Explanation:

ANSWER

Distance covered in nth second,

∝n

2

−(n−1)

2

∝n

2

−[n

2

+1−2n]

∝2n−1

n=2→2(2)−1=3

n=3→2(3)−1=5

n=5→2(5)−1=9

3:5:9