Question

For a freely falling object we can write Newton's second equation
of motion as​

Answer 1

Answer:

Therefore, Newton's second equation of motion for freely falling body is h = 1/2 gt^2

f

Answer 2

Answer:

Here you go mate,...

Explanation:

For a freely falling body, u=0, a=g (10m/s^2). Using these two informations and     the given pieces of information in the question we can solve any problem.

And as asked in the question the Newton's second law becomes H=1/2gT^2 (since u=0).

Also, as a tip,  you can use a short cut, FOR ANY BODY HAVING CONSTANT ACCELERATION AND INITIAL SPPED AS ZERO, THE DISTANCE COVERED BY THE BODY IN EQUAL INTERVALS OF TIME VARIES AS X:3X:5X:7X:9X:....

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