Question

for a frelly falling bady
V = ut---------​

Answer 1

For a freely falling body, these are the following equations of motions :-

$v \: = u + gt$

$h = ut + \frac{1}{2} g {t}^{2}$

${v}^{2} = {u}^{2} + 2gh$

Answer 2

Explanation:

V = ut + a

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First equation of Motion