Question

For a frequency distribution L=40,n=52,cf=28,f=8,h=10 then the median is

​

Answer 1

Answer:

Class Frequency Cumulative Frequency

0-10 12 12

10-20 13 25

20-30 25 50

30-40 20 60

40-50 10 70

Now

2

N

=35. Hence cumulative frequency just greater than 35 is 50. The corresponding class is 20−30.

Answer 2

Answer:

median= l+(n/2-cf )/f×h

40+(52/2-28)is divided by 8×10

40+(26-28) divided by 8 × 10

40+(-2)is divided by 8×10

40-20/8

320-20 is divided by 8

300÷8

37.5

there fore then the median = 37.5