Question

For a frequency distribution, l =40 n=52 cf =28 f=8 h=10 ,then find the median ​

Answer 1

Answer:

Class Frequency Cumulative Frequency

0-10 12-12

10-20 13-25

20-30 25-50

30-40 20-60

40-50 10-70

Now  2 N  =35. Hence cumulative frequency just greater than 35 is 50. The corresponding class is 20−30.

Step-by-step explanation:

OR

median= l+(n/2-cf )/f×h

40+(52/2-28) is divided by 8×10

40+(26-28) divided by 8 × 10

40+(-2) is divided by 8×10

40-20/8

320-20 is divided by 8

300÷8

=37.5

Therefore then the median = 37.5

Answer 2

Step-by-step explanation:

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