Question

For a frequency distribution, the mid-value of the class is 65 and the class size is 8 . What is the upper limit of the class ?​

Answer 1

Upper class limit us 65 + 4 = 69
Using the concept
midvalue + 1/2(class size)
65 + 4 = 69

Answer 2

SOLUTION

GIVEN

For a frequency distribution, the mid-value of the class is 65 and the class size is 8 .

TO DETERMINE

The upper limit of the class

CONCEPT TO BE IMPLEMENTED

Class Interval :

When the number of sample values are large in number and are in wide range, then the whole data is divided in a number of several groups according to the size of the sample. Each of these groups, made as above, is known as class interval

Class Length :

Class Length or Class Size or Class Width of the class interval of any class is defined to be the difference between the lower and upper class boundaries ( not class limits) of that particular class interval.

Class length = Upper Class boundary - Lower class boundary

Upper limit :

In the frequency table if both ends of any class interval are specified then these end values are known as class limits. The lower end value is called lower class limit whereas the upper end value is called upper class limit

EVALUATION

Here it is given that for a frequency distribution,

The mid-value of the class = 65

The class size = 8

Hence the required upper limit of the class

$\displaystyle \sf{ = Mid \: Value + \frac{Class \: Size }{2} }$

$\displaystyle \sf{ = 65 + \frac{8 }{2} }$

$\displaystyle \sf{ = 65 +4 }$

$\displaystyle \sf{ =69}$

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ The value of mean, median and mode can never be equal. Is it true or false

https://brainly.in/question/36450784

2. For 10 observations if mean and variance of the series is 16 and 20 respectively then sum of square of all observation i...

https://brainly.in/question/34371921