Question

for a frequency distribution the mid value of the class is 150 and the width of the class is 20 what is the lower limit

Answer 1

Let the lower limit be x

∴upper limit =(x+8) (∵ class size is 8)

mid value of class =(upper limit +lowerlimt)÷2

⇒20 =[(x+8)+x]÷2

⇒40=2x+8

⇒40 - 8 =2x

⇒32 =2x

∴x =16

this is your answer

Answer 2

Answer:

The mid value of a classes is 150 and the width of the classes is 20, then lower limit of class is: