Question

for a g.p. a=4/3 and t7=243/1024 find the value of r​

Answer 1

Answer:

$\bf\:r=\pm\frac{3}{4}$

Step-by-step explanation:

For a g.p. a=4/3 and t7=243/1024 find the value of r​

Given:

$a=\frac{4}{3}$

$t_7=\frac{243}{1024}$

using

$\boxed{\text{n th term of G.P is }t_n=ar^{n-1}}$

$\implies\:ar^6=\frac{243}{1024}$

$\implies\:(\frac{4}{3})r^6=\frac{243}{1024}$

$\implies\:r^6=\frac{729}{4096}$

$\implies\:r^6=\frac{3^6}{4^6}$

$\implies\:r^6=(\frac{3}{4})^6$

$\implies\:\boxed{\bf\:r=\pm\frac{3}{4}}$

Answer 2

Answer:

r=+3/4

Step-by-step explanation:

=ar⁶=243/1024

=(4/3)r⁶=243/1024

=r⁶=729/4096

=r⁶=3⁶/4⁶

=r⁶=(3/4)⁶

r=+3/4