Question

for a G.P if a=6 ,r=2 ,find S10​

Answer 1

∴ $S_{10}$ = 6($2^{10}$ - 1)

Step-by-step explanation:

Here, first term(a) = 6, common ratio(r) = 6 and n = 10

To find $S_{10}$ = ?

We know that,

$S_{n}$ = $\dfrac{a(r^{n} -1)}{r -1 }$

∴$S_{10}$ = $\dfrac{6(2^{10} -1)}{2 -1 }$

= 6($2^{10}$ - 1)

Hence, $S_{10}$ = 6($2^{10}$ - 1).

Answer 2

Answer:

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