for a G.P.if t3=1/3,t6=1/81 find r
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Given,
In a G.P., t3 = 1/3
t6 = 1/81
To find,
The value of r.
Solution,
The value of r will be 1/3.
We can easily solve this problem by following the given steps.
We know that in a G.P. the ratio of the two consecutive terms is common which is called the common ratio. It is denoted by r.
According to the question,
t3 = 1/3
t6 = 1/81
We know that the formula to find the nth term in GP is given as follows:
tn = ar^(n-1)
t3 = ar^(3-1)
ar² = 1/3 --- equation (1)
t6 = ar^(6-1)
ar^5 = 1/81 ---- equation (2)
Dividing equation 2 by equation 1,
ar^5÷ar² = 1/81 ÷ 1/3
r³ = 3/81
r³ = 1/27
r³ = 1/(3)³
r³ = (1/3)³
r = 1/3
Hence, the value of r is 1/3.
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