Math, asked by manavprasanth77, 6 months ago

For a G.P the ratio of the 7 th and the third terms is 16.The sum of 9 terms is 2555. What is the first term?

Answers

Answered by amitnrw
0

Given : For a G.P. the ratio of the 7th and the third terms is 16.

The sum of 9 terms is 2555.

To Find : the sequence.

Solution:

For a G.P. the ratio of the 7th and the third terms is 16.

aₙ = arⁿ⁻¹

a = first term

r = common ratio

n = number of term

7th term = ar⁶

3rd tern = ar²

ratio of the 7th and the third terms is 16.

=> ar⁶/ar² = 16

=> r⁴ = 16

=> r = ± 2

Sₙ  = a(rⁿ - 1)/(r- 1)

The sum of 9 terms is 2555.

case 1 :  r  = 2

=> a(2⁹ - 1)/(2 - 1)  = 2555

=> a  (512 - 1) = 2555

=> a =  5

So sequence is

5 , 10 , 20 , 40 , 80 , 160 , 320 , 640 , 1280

case 2 :  r  = -2

=> a((-2)⁹ - 1)/(-2 - 1)  = 2555

=> a  (-512 - 1)/(-3) = 2555

=> 171a =  2555

=> a = 2555/171

So sequence is

2555/171 , -2* 2555/171  , 4 *2555/171  , - 8 *2555/171  and so on

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