Question

For a gas molecule with 6 degrees of freedom, the
law of equipartion of energy gives the following
relation between the molecular specific heat
(Cv) and gas constant (R)
(A) Cv= R/2
(B)Cv=R
(C) Cy = 2R
(D)cv=2r
Cy= 3R​

Answer 1

Answer:

The answer is a option B

Answer 2

Answer:

answer is option b...pls mark me as a brainlist

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