Question

for a gas reaction
3h2+n2 gives 2nh3
the partial pressure of h2 and n2 are 0.4 , 0.8 atmospher. The total pressure of entire system is 2.8 atmospher . What will be the value of kp if all the concentration given are in atmosphere.

Answer 1

N2 + 3H2 ↔ 2NH3
partial pressures of H2 and N2 are 0.4 and 0.8 atm
so partial pressure of 2NH3  = 1.6 atm
Kp= [NH3] ^2 / ( [N2] [ H2]^3 )
= 1.6 ^ 2 / 0.8 * 0.4 ^3
= 2.56 / 0.0512
= 50
Please approve !


or


if partial pressures tht u hav givn fr h2 nd n2 r at equilibrium thn...
presure of nh3=1.6
so kp=(1.6)^2/0.8*(0.4)^3

7 years ago

N2      +      3H2     =>    2NH3
0.4            0.8                  P                 (at equilibrium)
sum of all pressure = P(total) = 1.2 + p = PT
  PT  = 2.8 (given)  so
 1.2 + P = 2.8
         pNH3 = 1.6
now Kp =  ( pNH3)2 /(PN2)(pH2)3
           = (1.6)2/(0.4)(0.8)3
          Kp =  12.5 (atm)-2

Answer 2

Explanation:

so this is the correct answer