Question

for a gas the rms speed at 800K is n times That at 200K. the value of n is​

Answer 1

Answer:

hey mate!

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Explanation:

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check the answer!

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Solution:                 Answer:        Twice the value at 200 K

                             Vrms = √(3RT / Mo)

                   hence

                             Vrms ∝ √T

                             {Vrms2 / Vrms1} = √(T2 / T1)

                   T1 = 800K. Let T2 = 200K

                   then {Vrms2 / Vrms1} = √{200 / 800} = (1/2)

                             i.e. Vrms1 = 2 × Vrms2

                   i.e. RMS velocity at 800K i.e. Vrms1 is twice of Rms Velocity at 200 K   .

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Answer 2

The rms speed at 800 K is two times of rms speed at 200 K.

Explanation:

The rms speed of the gas molecules is given by :

$v_{rms}=\sqrt{\dfrac{3RT}{M}}$

R is gas constant

T is temperature

M is molar mass

It is clear that,

$v_{rms}\propto \sqrt{T}$

So,

$\dfrac{v_1}{v_2}=\sqrt{\dfrac{T_1}{T_2}}$

Let T₁ = 800 K and T₂ = 200 K

$\dfrac{v_1}{v_2}=\sqrt{\dfrac{800}{200}}\\\\\dfrac{v_1}{v_2}=2$

So, it is clear that the rms speed at 800 K is two times of rms speed at 200 K. Hence, n = 2

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