Question

for a gas where volume and pressure are 1dm^3 and 2 atm.what should be its new volume when pressure is increased to 6 atm at constant temperature

Answer 1

Here,
we have to use Boyle's law

${P_1}$${V_1}$=${P_2}$${V_2}$

1L×2atm=6atm ${V_2}$

$new \: volume = \frac{1}{3} litres$