Physics, asked by Ramees3211, 19 days ago

For a gaseous reaction 2A2(g)+5B2(g)→2A2B5(g) at 27∘C the heat change at constant pressure is found to be −50160J. Calculate the value of internal energy change (ΔU).(R=8.314J/Kmol)

Answers

Answered by sahilpatil3356
0

Answer:

2A2(g)+5B2(g)=2A2B5(g)

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