Chemistry, asked by dollsanjanaverma, 20 days ago

For a gaseous reaction pA + pB = qC + qD
(1) Kp= Kc
(ii) kp =kc(RT)^(p+q)
(ii) kp=kc (RT)^(p-q)
(iv) kp= kc(RT)^1/(p+q)​

Answers

Answered by malepatiakhilesh
0

Explanation:

answer is iii. ∆n value is 2(p-q). substitute the value in kp=kc(RT)^∆n

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