For a gaseous system find change in internal energy if the heat supplied to the system is 50 J and work done by the system is 16 J.
Answers
Answered by
0
Answer:
change in internal energy is 34 joules
Explanation:
from first law of thermodynamics
dq=du+dw.
50j=du+16j
du=34j
Answered by
0
Answer:
Change in internal energy of the system, ΔU, is 34 J.
Explanation:
Given,
For a gaseous system,
- Heat provided to the system, Q = 50 J
- Work done by the system, W = +16 J
As word done by the system is taken as positive in physics.
- Change in internal energy of the system, ΔU = ?
As we know,
- The first law of thermodynamics is based on the principle of conservation of energy. It states that total energy of a system remains constant, it energy can be transformed from one form to another form, but can neither be created nor be destroyed.
So, according to the first law of thermodynamics,
- ΔU = Q - W
- ΔU = 50 - 16
- ΔU = 34 J
RESULT: For a gaseous system, if the heat supplied to the system is 50 J and work done by the system is 16 J, then the change in internal energy is 34 J.
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