Question

For a general chemical change 2A+3B
the rate of disappearance of A is r, and
B is r2. The rates r, and r, are related as :-
(1) 3r, = 2r2
(2) r = r₂
(3) 2r, = 312 (4) r² = 2r2²
13.​

Answer 1

Answer:  $3r=2r_2$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2A+3B\rightarrow Products$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$Rate=-\frac{1d[A]}{2dt}=-\frac{1d[B]}{3dt}$

Given: Rate of disappearace of A = $\frac{-d[A]}{dt}]=r$

Rate of disappearace of B = $\frac{-d[B]}{dt}]=r_2$

Putting in the values we get:

Thus $\frac{r}{2}=\frac{r_2}{3}$

$3r=2r_2$

Answer 2

Answer:

3r1=2r2 is the correct answer