for a given Ap 2, 7 , 12 ,17 ------ sum of how many terms is 990
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Let a be the first term and d be the common difference.
Given series is 2,7,12,17... 990.
Here,
= > a = 2, n = 990
d = 7 - 2 = 5.
We know that sum of n terms of an AP sn = (n/2)[2a + (n - 1) * d]
= > (990/2)[2(2) + (990 - 1) * 5]
= > 495[4 + (989) * 5]
= > 495[4949]
= > 2449755.
Hope this helps!
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