Chemistry, asked by Sciencenonfiction, 2 months ago


For a given exothermic reaction, Kp and K'p are the equilibrium constants at temperatures T, and
To, respectively. Assuming that heat of reaction is constant in temperature range between T, and
Ty, it is readily observed that
(1) Kp>K
(2) Kp<K
(3) Kp K's (4)
{k}p =  \frac{1}{kdash}

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Answers

Answered by anjupundir6530
0

Answer:

For a given exothermic reaction, Kp and K'p are the equilibrium constants at temperatures T, and

To, respectively. Assuming that heat of reaction is constant in temperature range between T, and

Ty, it is readily observed that

(1) Kp>K

(2) Kp<K

(3) Kp K's (4)

{k}p = \frac{1}{kdash}

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