Question

For A Given Frequency Distribution C.V = 30%, Variance = 36 And Pearson's Coefficient Of Skewness = -0.25, The Mode Of The Distribution Is​

Answer 1

Answer:

Answer»21.5

Step-by-step explanation:

Answer 2

Given :

Co-efficient of variance = 30%

Variance = 36

Pearson's Coefficient Of Skewness = -0.25

To Find :

The Mode Of The Distribution

Solution :

We know, co-efficient of variance = $\frac{Standard Deviation}{Mean}$ × 100

As, Standard Deviation (S.D) = √Variance

                                       = √36

                                       = 6

Now,   co-efficient of variance = $\frac{6}{Mean}$ × 100

or,                       30                   = $\frac{600}{Mean}$

or,                   Mean                  = $\frac{600}{30}$

∴                     Mean                  = 20

∴ Karl Pearson's coefficient of skewness = $\frac{Mean - Mode}{S.D}$

or,                         - 0.25                             = $\frac{20 - Mode}{6}$

or,                           - 1.5                              = 20 - Mode

or,                          Mode                            = 20 + 1.5

∴                           Mode                            = 21.5

∴ The Mode Of The Distribution Is​ 21.5