Physics, asked by metricspace60771, 8 months ago

For a given material, the energy and wavelength of characteristic X-rays satisfy
(a) E(Kα) > E(Kβ) > E(Kγ)
(b) E(Mα) > E(Lα) > E(Kα)
(c) λ(Kα) > λ(Kβ) > λ(Kγ)
(d) λ(Mα) > λ(Lα) > λ(Kα).

Answers

Answered by muhammad4499
0
C is the right answer
Answered by bhuvna789456
0

The energy and wavelength of characteristic X-rays satisfy \lambda(\mathrm{K} \alpha)>\lambda(\mathrm{K} \beta)>\lambda(\mathrm{K} y) and \lambda(\mathrm{M} \alpha)>\lambda(\mathrm{L} \alpha)>\lambda(\mathrm{K} \alpha).

Explanation:

  • The transition of Kγ to the K shell from the N shell includes more energy than the Kβ transition to the K shell from the M shell.
  • More than the Kα transition to the K shell from the L shell, Kβ transition has more energy.
  • With the wavelength, the energy varies inversely, \lambda\left(\mathrm{K}_{\mu}\right)<\lambda\left(\mathrm{K}_{\beta}\right)<\lambda\left(\mathrm{K}_{\mathrm{a}}\right).
  • When the electrons jump to the M shell from the N shell, Mα transition takes place. This involves the energy lesser than the Lα transition to the L shell from the M shell. This involves low energy than the transition of Kα to the K shell from the L shell.
  • With the wavelength, the energy varies inversely, \lambda\left(\mathrm{K}_{\mu}\right)<\lambda\left(\mathrm{K}_{\mathrm{B}}\right)<\lambda\left(\mathrm{K}_{\mathrm{a}}\right).
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