Question

For a given material Y=16*1080 N/m' and poisson's ratio is 0.3. Then its
compressibility is ............... m/
| (A) 1333- 1050
(B) 0.075x10 છે.
(C) 13.3310-10
(D) 0.025x10"
​

Answer 1

Answer:

B) $0.075 X 10^{-8}$

Explanation:

E=3K(1-2μ)

where E= modulus of elasticity (Young's modulus)

           K=Bulk modulus( or 1/compressibility )

           μ=Poisson's ratio

$\frac{1}{k}=\frac{3(1-2u)}{E}$=$0.075 X 10^{-8}$