Question

for a given medium the polarizing angle is 60 degree what will be the critical angle for this medium?​

Answer 1

Answer:

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Explanation:

From Brewster's law  

The refractive index of the medium is given by  

n=$tani_{p}$

where $i_{p}$= polarizing angle

⇒n=tan$60^{o}$

⇒n=  $\sqrt{3}$

​If C be the critical angle for the medium then,

n=  $\frac{1}{sinC}$

sinC=$\frac{1}{n} =\frac{1} \sqrt{3}$

C=$sin ^{-1}$($\frac{1}\sqrt{3}$)

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