For a given order reaction, the half life is 0.5 minute, at a given temperature. Calculate the time needed for
75% of the reactant to decompose.
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Answer:
t = 0.99932 minute
Explanation:
Given = t1/2 = 0.5 minutes
to find= t such that 75% of reactant get decompose
So let us assume at ;
a) t = 0 ⇒ 100% reactant present = [A]o
b) t = x ⇒ 100-75 = 25 % reactant present [A]x
we know that ; k= 2.303/t ㏒[A]o/[A]x
to find k we use the formula ;
for first order reaction : t1/2 = 0.693/k
therefore= k = .693/.5⇒ 1.386
putting the value we get : t = 2.303/1.386 log[100]/[25]
t = 0.99932 minute
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