Question

For a given relationship a(302)b/20b=(12.1)b the value of b is

Answer 1

Answer:

Consider, 302 = 3b² + 0b + 2

20 = 2b + 0

12.1 = 1b + 2 + 1/b

Now,

(3b² + 2) / 2b = b + 2 + 1/b

3b² + 2 = 2b² + 4b + 2 [ multiplying by 2b ]

b² = 4b

So, b = 4

Therefore, base is 4.

Thanks you.