Question

For a given speed of projection, maximum range of
a projectile is R. What will be the maximum height
attained by projectile when it is projected with
double speed by making 60° with vertical?
(1) R/2. (2)R/4. (3)R. (4)3R/2​

Answer 1

Answer:

This is the duplet (or duet) rule. Here are additional clarifications: The octet rule is a chemical rule of thumb that reflects observation that atoms of main-group elements tend to combine in such a way that each atom has eight electrons in its valence shell, giving it the same electronic configuration as a noble gas

Answer 2

Answer:

Maximum height, $H=\dfrac{3R}{2}$

Explanation:

The maximum range of the projectile is given by :

$R=\dfrac{u^2\ sin2\theta}{g}$

For maximum range of a projectile, $\theta=45$

$R=\dfrac{u^2}{g}$

$u=\sqrt{Rg}$

The maximum height attained by the projectile when it is projected with  double speed is given by :

$H=\dfrac{u^2\ sin^2\theta}{2g}$

$H=\dfrac{(2\sqrt{Rg})^2\ sin^2(60)}{2g}$

$H=\dfrac{3R}{2}$

So, the maximum height attained by the projectile is 3R/2. Hence, this is the required solution.