Question

For a given value of k, the product of the zeroes of x²–3kx + 2k² is 7, then zeroes are
a) a rational number
b) irrational number
c) one rational other irrational
d) none of these

Answer 1

Answer:

option b

Step-by-step explanation:

Given :-

The product of the zeroes of x²–3kx + 2k² is 7

To find :-

Find the value of k ?

Solution:-

Given Polynomial = P(x) = x²–3kx + 2k²

On comparing with the standard quadratic polynomial ax²+bx+c then

a = 1

b = -3k

c = 2k²

We know that

Product of the zeroes = c/a

=> 2k²/1

=> 2k²

According to the given problem

Product of the zeroes = 7

=> 2k² = 7

=> k² = 7/2

=> k = ±√(7/2)

=> k = √(7/2) or -(√7/2)

Answer:-

The values of k for the given problem are √(7/2) or -(√7/2)

Irrational numbers.

Used formulae:-

• The standard quadratic polynomial is ax²+bx+c
• Product of the zeroes = c/a
• Sum of the zeroes = -b/a