Question

. For a glass prism of refracting angle 60°, the minimum angle of deviation Dm is found to be 36
with a maximum error of 1.05°. When a beam of parallel light is incident on the prism, find the
range of experimental value of refractive index 'u'. It is known that the refractive index 'u' of the
material of the prism is given by
A+Dm
sin
2.
U =
sin(A/2)​

Answer 1

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Answer:

Explanation:

Refracting angle of glass prism = A = 60° (Given)

Refractive index of glass prism = 1.5 (Given)

Refractive index of water = 1.33 (Given)

Refractive index of the material of the prism = µ

The refractive index -

µ1 =$sin (A + δ)/2/ sin A/2$

= $sin{(60+Dm)/2}/sin30° = 1.5/1.33$

= $sin{30+(Dm/2)} =1.5×(1/2 )= 1.12$

=$30°+(Dm/2) =sin-1(0.75) = 38.43$

= (Dm/2) = 38.43–30

= 8.43°