Question

For a GP if a=7, r= -3, then t6= ?
O -1711
O 1701
O -1701
O 1711​

Answer 1

SOLUTION

TO CHOOSE THE CORRECT OPTION

For a GP if a=7, r= -3, then $\sf{ t_6} =$

• - 1711

• 1701

• - 1701

• 1711

CONCEPT TO BE IMPLEMENTED

For a given geometric progression

First term = a

Common Ratio = r

Then n th term

$= \sf{ t_n}$

$= \sf{a \times {r}^{n - 1} }$

EVALUATION

Here it is given that

For a given geometric progression

First term = a = 7

Common Ratio = r = - 3

Hence

$\sf{ t_6}$

= 6 th term

$\sf{ = 7 \times {( - 3)}^{6 - 1} }$

$\sf{ = 7 \times {( - 3)}^{5} }$

$\sf{ = 7 \times ( - 243)}$

$= - 1701$

FINAL ANSWER

Hence the correct option is - 1701

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