For a graph shape of straight line sloping up starting from origin, between “distance” and “time”, use 2nd equation of motion to deduce the relationship “distance α time”
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Explanation:
s=ut+1/2at^2
here the acceleration is zero as in the distance-time graph then s=ut
if the graph is a velocity-time graph then the acceleration is present
but u will be zero so s=at^2
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