Question

For a half cell having reaction - 1/2Cl2 + e→ Cl-, if1MCI- solution is diluted to 100 times(E°Cl2/2cl- = 1.36V), then Ecl2/2cl-will be (GivenPcl2= 1atm)(1) 1.18 V(2) 1.48 V(3) 1.68 V(4) 3.48 V​

Answer 1

Answer:

(2) 1.48

Explanation:

The ans is 1.48

just use the NERNST EQUATION

put all the values in the equation and get ans....

Answer 2

Answer is 1.48 V

Explanation:

• Nernst equation

The relation between Electrochemical Reaction's Reduction Potential (For Half Cell/Fuel Cell) and Activities as temperature, electrode potential, and actions of oxidation/reduction with a chemical substance.

• here, we will use the NERST Equation.

$E_{cell} = E_{cell}^{'} - \frac {0.0591}{n}log\frac {Product}{Reactant}$ """(a)

$E_{cell}^{'} = 1.36\ V$

with Product = $\frac {R}{100} = \frac {1}{100}$

Using the above significant factors in equation (1)-

$E_{cell} = 1.36 - \frac {0.0591}{1}log\frac {1}{100}$  (As we know that log $\frac {1}{100}$= log $10^{-2}$= -2)

= 1.36 - 0.0591 $\times$ -2

= 1.36 + 0.1182

= 1.478 V or 1.48 V