Question

for a heater rated at 4 kilowatt and 220 volt calculate the energy consumed in 2 hour​

Answer 1

$\Huge{\underline{\underline{\blue{\mathfrak{Answer :}}}}}$

$\Large{\sf{Given :}}$

• Power = 4 kW ⟹ 4000 W
• Time (t) = 2 hrs
• Potential Difference (v) = 220 V

$\rule{200}{2}$

$\LARGE{\sf{To \: Find :}}$

Energy consumed

$\rule{200}{2}$

$\LARGE{\sf{Solution :}}$

$\LARGE{\boxed{\boxed{\green{\tt{Energy \: = \: Power \: \times \: time}}}}}$

→ Energy = (4000)(2)

→ Energy = 80000

→ Energy = 8 kWh

$\Large{\boxed{\red{\sf{Energy \: = \: 8 \: kWh}}}}$

$\rule{200}{2}$

$\LARGE {\underline{\underline{\sf{Important \: Formulas }}}}$

• P = VI
• V = IR
• H = VIt
• V = W/Q
• P = I²R

Where,

P is Power

V is Potential Difference

H is heat energy

W is work done

t is time

I is current

Q is charge

R is resistance

Answer 2

$\bold{\large{\underline{\underline{\sf{StEp\:by\:stEp\:explanation:}}}}}$

Power = 4 kW ⟹ 4000 W

Time (t) = 2 hrs

Potential Difference (v) = 220 V

$\green{\tt{To \: Find :}}$

Energy consumed

$\bold\green{\tt{Solution }}$

${\boxed{\blue{\sf{Energy \: = \: Power \: \times \: time}}}}$

→ Energy = (4000)(2)

→ Energy = 80000

→ Energy = 8 kWh

${\boxed{\blue{\tt{Energy \: = \: 8 \: kWh}}}}$

$\blue{\underline{\tt{Important \: Formulas \: used}}}}$

• P = VI

•V = IR

•H = VIt

•V = W/Q

•P = I²R

Where,

P is Power

V is Potential Difference

H is heat energy

W is work done

t is time

I is current

Q is charge

R is resistance