Question

For a heater rated at 4 kW and 220 V, calculate :
(a) the current,
(b) the resistance of the heater,
(c) the energy consumed in 2 hours, and
(d) the cost if 1 kWh is priced at * 4.60​

Answer 1

Given, P=4kW , V=220V

a) I =?

P=VI=250×I

4000=250×I

I=16amp

b)R=?

P=I^2R

P=16^2×R

R=4000/16^2

R=15.25ohm

c)energy consumed in two hour=P×t =4×2 =8kW-h

d)if 1kWh=₹4.6

total cost = 8×4.6=₹36.8