For a heater rated at 4 kW and 220 V, calculate
(a) the current
(1) the resistance of the heater,
(c) the energy consumed in 2 hours, and
(d) the cost it 1 kWh is priced at 4.60
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Answer:
Given
P=4kW,V=220V
(a) I=?
Power=VI=250×I
4000=250×I
I=16amp
(b) R=?
P=I
2
R
P=16
2
×R
R=4000/16
2
R=15.25ohm
(c) Energy consumed in two hour =P×t
=4×2
=8kW−hr
(d) If 1kWh=Rs.4.6
total cost =8×4.6=Rs.36.8
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