Question

for a heater rated at 4kw and 220V calculate

1. current

2.resistance of heater

3.energy consumed in 2 he

4. cost if 1Kwh is priced at 50 paise..

Answer 1

Heya!!

1) Since P = V * I

=) I(current) = 4 kW/ 220

= 4000/220

= 18.1 Ampere

2) Since R(Resistance) = V^2 /P

= 220^2 / 4000

= 12.1 ohms

3) Energy in 2 hrs = P*t

= 4 * 2

= 8 KWhr

4) cost at 50 paise = ₹8 *0.5

= ₹4

Hope it helps uh!!

Answer 2

$\huge{hey}$

$\huge{ \mathfrak{here \: is \: answer}}$
$\bf{given}$

power =4kw=4000w

potential difference = 220v

Time = 2hr =7200sec


$\sf{1. \: i = \frac{p}{v}}$


$\sf{ \: i \: = \frac{4000}{220}}$

$\bf{i = 18.1 \: ampere}$


$\sf{2. \: resistence = \frac{v}{i} }$


$\sf{r = \frac{220}{18.1}}$

$\bf{r = 12.1ohm}$


$\sf{3. \: energy = p \times t}$

$\sf{e = 4 \times 2}$

$\bf{e = 8kw \times hr}$

$\sf{4. \: cost = e \times rate}$


$\sf{8 \times \frac{50}{100}}$
$\bf{rupees \: 4.0}$

$\huge \boxed{hope \: it \: helps}$


$\huge{ \mathbb{THANKS}}$