Question

for a heater rated at kW 4 kw and 220 V calculate current and resistance the energy consumed in 2 hr and last the cost of if (1 kwh is priced at 50 paise .?

Answer 1

hello@


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here is u r answer ##

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=> according to question given :-

power (p)= 4kWh = 4 W .

potential difference (v)=220 v.

Time (t) = 2hr =7200 s.

find

1. current (I)=?

2.resistance (R) =?

3.energy consumed (E )= ?

4.cost =?.

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formula to be used :

1.I =p /v

2.R = V/ I.

3.E = p / t.

4. cost = t × Rate.

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substituting the given values ,we get

1. current (I) = 4000/ 220 = 18.1 A.

2.Resistance (R)= V / I = 220 / 18.1 = 12.1 ohm.

3. Energy (E) = P × t = 4×2 = 8 kilowatt × hr

4.cost = E × rate = 8 × 50 / 100= ₹ 4.00.

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I HOPE HELP U :):)

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### RISHU ###

Answer 2

Answer:

1. current (1) = 4000/ 220 = 18.1 A.

2.Resistance (R)= V/I= 220 / 18.1 = 12.1 ohm.

3. Energy (E) = Pxt = 4x2 = 8 kilowatt x hr

4.cost = Ex rate = 8 x 50 /100= 4.00.

Explanation:

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