Question

For a hypothetical ion X-2. If it has atomic number (z) = 14 and mass number (A) = 30. Then the sum of electrons protons and neutrons present in X+2 is.

Answer 1

Answer:

Explanation:

Let x be the number of electrons.  

The number of  neutrons is x+0.111x=1.111x.

The number of protons is x−1.

The mass number is 37.  

It is equal to the sum of the number of protons and the number of neutrons.

x−1+1.111x=37

2.111x=38

x=18

The number of electrons is 18.

The number of protons is 17.

Hence, the symbol of the ion is  

17

37

​

Cl  

−

.

Answer 2

Sum of electrons, protons and neutrons present in $\bf {X}^{ + 2}$ are 42.

Given:

• A hypothetical ion ${X }^{ - 2}$.
• Atomic number (z)= 14, mass number (A)=30.

To find:

• Find the sum of electrons protons and neutrons present in ${X}^{ + 2}$.

Solution:

The number of protons in the element are 14, i.e. the atomic number.

As,

The mass number is 30.

Mass number= Number of protons+Number of neutrons

Thus,

The number of neutrons are= 30-14

The number of neutrons are 16.

Number of electrons in neutral atom X are 14, as number of electrons and protons are equal in an element.

Number of electrons in ion ${X}^{ - 2}$ are 14+2 , i.e. 16.

Number of electrons in ${X}^{ + 2}$

are 14-2= 12

Thus,

$\bf {X}^{ + 2}$ have 14p, 12e and 16n.

Sum of protons, electrons and neutrons in

${X}^{ + 2}$ are$= 14 + 12 + 16$

Thus,

Sum of protons, electrons and neutrons in

$\bf {X}^{ + 2}$ are 42.

Learn more:

1) Calculate the number of protons neutrons and electrons in 35 br 80

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2) Write IUPAC names of the given compound.

https://brainly.in/question/6266976

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