Question

for a hypothetical reaction,2A +3B -->C,initially 6 moles of A and 8 moles of B were taken.Assuming 100% efficiency of the reaction,Moles of C formed at the end of reaction?​

Answer 1

Answer:

2.67 moles of C

Explanation:

2A + 3B → C

This means 2 mole of A reacts with 3 moles of B to produce 1 mole of C.

Now you have taken 6 moles of A. (3 times more than single reaction)

So it will need 9 moles of B to react completely.

But you have taken only 8 moles of B.

Thus, the reaction will be limited because you have lesser number of moles of B than required,i.e. B is the limiting reagent. So the amount of C produced will depend on amount of B only.

Now according to equation,

3 moles of B form = 1 mole of C

So, 8 moles of B will form = 8/3 x 1 = 2.67 moles of C