Question

For a light ray passing through a prism angle of incidence is I1, andangle of emergence is I2. In case of minimum deviation of the ray.A. I1 = I2B. I1,>I2C. l1,<I2D. None​

Answer 1

Answer:

For minimum deviation of light through prism the condition is i1 = i2

Explanation:

As we know that angle of incidence and angle of emergence is given

so deviation of light ray is given as

$\delta = (i_1 - r_1) + (i_2 - r_2)$

here we know

$r_1 + r_2 = A$

so we have

$\delta = i_1 + i_2 - A$

now for minimum deviation angle we know that

$r_1 = r_2$

so we have

$i_1 = i_2$

#Learn

Topic : Prism

https://brainly.in/question/1284429