For a liquid normal boiling point is 173°C then at 2 atm pressure,what should be it's boiling point
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if the volume is constant,
p1/t1=p2/t2
=>1/(273+173)=2/t2
=>t2=446×2
=>t2=892
=>t2=(892-273)°C
=>t2=619°C
so the new boiling point would be 619°C
p1/t1=p2/t2
=>1/(273+173)=2/t2
=>t2=446×2
=>t2=892
=>t2=(892-273)°C
=>t2=619°C
so the new boiling point would be 619°C
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