Question

For a man who walks 720 m at a uniform speed of 2 m/s, then runs at a uniform speed of 4 m/s for
5 minute and then again walks at a speed of 1 m/s for 3 minutes. His average speed is
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Answer 1

Answer:

2.333m/sec

Explanation:

sum of the speeds = 2+4+1 =7

no of observation =3

for the average speed divide sum by observation=

7/3 =2.333

therefore the answer to this questions is 2.333m/sec

Answer 2

Case-1;

Speed=2m/sec

Distance=720m=d1

Time=d/s

=720/2=360sec =t1

Case;

Speed=4m/sec

Time =5min=5*60=300sec=t2

Distance =s×t

=4*300=1200m =d2

Cases;

Speed=1m/s

Time=3min=3×60 =180sec=t3

D=s×t

=180*1=180m=d3

Therefore,

Avg. Speed =total distance / total time

=d1+d2+d3/ t1+t2+t3

=720+1200+180/360+300+180

=2100/840

=2.5m/sec

*****avg.speed=2.5m/sec*******