Question

for a man who walks 720 m at a uniform speed of 2m/s then runs at a uniform speed of 4 m/s for 5 minutes and then again walks at a Speed of 1 m/s for 3 min. his average speed is??​

Answer 1

Step-by-step explanation:

Where s1 =720 m and t1 = s1/v1 = 720/2 = 360 s

s2 = (4)(5)(60) = 1200 m,t2 = 300 s

s3 =(1)(3)(60)= 180 m , t3 = 180 s

vavg=s1+s2+s3t1+t2+t3

Vavg =S1+S2+S3

__________________

t1+t2+t3

Vavg=720+1200+180

________________

360+300+180

=2.5