Question

For a mass of 2kg, the velocity time graph is given is given here. Find the force experienced by the mass in regions OA,AB and BC​

Answer 1

Given:

For a mass of 2kg, the velocity time graph is given.

To find:

Force experienced in OA , AB and BC parts ?

Calculation:

• In order to calculate force, first we need to calculate the acceleration experienced by the particle in those parts of the graph.

• Acceleration can be calculated by the slope of velocity-time graph.

In OA :

$\sf \therefore \: force = mass \times acceleration$

$\sf \implies \: force = 2 \times \dfrac{\Delta v}{\Delta t}$

$\sf \implies \: force = 2 \times \dfrac{20 - 0}{5 - 0}$

$\sf \implies \: force = 8 \: newton$

In AB:

$\sf \therefore \: force = mass \times acceleration$

$\sf \implies \: force = 2 \times \dfrac{\Delta v}{\Delta t}$

$\sf \implies \: force = 2 \times \dfrac{20 - 20}{40 - 5}$

$\sf \implies \: force = 0 \: newton$

In BC:

$\sf \therefore \: force = mass \times acceleration$

$\sf \implies \: force = 2 \times \dfrac{\Delta v}{\Delta t}$

$\sf \implies \: force = 2 \times \dfrac{0 - 20 }{45 - 40}$

$\sf \implies \: force = - 8 \: newton$

Hope it helps.

Answer 2

Force= mass x acceleration

In OA

a= (20-0)/(5-0) = 4m/s²

Force= 2 x 4 = 8N

In AB

a= (20-20)/(40-5) =0m/s²

Therefore,

Force= 2 x 0 = 0 N

In BC

a= (0-20)/(45-40) = - 4m/s ²

Therefore,

Force= 2x (-4) = -8 N

Thank You....