Question

For a Mathematics test given to 15 students, the following marks (out of 100) are recorded.
41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60.
Find the mean, median and mode of this data.For a Mathematics test given to 15 students, the following marks (out of 100) are recorded.
41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60.
Find the mean, median and mode of this data.

Answer 1

Answer:

here is your answer mate!!!!!!

Answer 2

$\huge\bold\red{Question}$

For a Mathematics test given to 15 students, the following marks (out of 100) are recorded.

41, 39, 48, 52, 46, 62, 54, 40, 96, 52, 98, 40, 42, 52, 60.

Find the mean, median and mode of this data.

$\huge\bold\green{Solution}$

$\sf{Mean=Average =}$ $\sf{\frac{Sum \: of \: all \: the \: observations}{Total \: number \: of \: observations}}$

$\sf{\frac{(41+39+48+52+46+62+54+40+96+52+98+40+42+52+60)}{15}}$

= $\sf{\frac{822}{15}}$

= $\sf{54.8}$

$\sf{Median,}$

$\sf{To\: find\:the\:median,\:we\:first\:arrange\:the}$ $\sf{data\: in\:ascending\:order.}$

$\sf{39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54,}$ $\sf{60, 62, 96, 98}$

$\sf{Here,}$

$\sf{Number\: of\: observations\: (n) = 15}$

$\sf{Since\: the \:number\: of\: observations\: are}$ $\sf{odd, \:the\: median \:can \:be \:calculated \:as:}$

$\sf{Median}$ = $\sf{[\frac{(n+1)}{2}]th}$ $\sf{observation}$

= $\sf{(\frac{15+1}{2})th \:observation}$

= $\sf{(\frac{16}{2})th \:observation}$

= $\sf{8th\:observation}$

= $\sf{52}$

$\sf{Mode,}$

$\sf{To\: find\:the\:mode,\:we\:first\:arrange\:the}$ $\sf{data\: in\:ascending\:order.}$

$\sf{39, 40, 40, 41, 42, 46, 48, 52, 52, 52, 54,}$ $\sf{60, 62, 96, 98}$

$\sf{Here,}$

$\sf{We\:find\:that\:52\:occurs\:most\:frequently}$$\sf{(3 \:times)}$

$\sf{∴\: Mode = 52}$