Question

For a mixture of NO3 and SO2, having 25 moles and 100 moles respectively. The total pressure exerted by the gases is 100 atm. What is the partial pressure of NO3?​

Answer 1

Explanation:

Since the number of moles of CO and nitrogen are equal, their mole fractions will be 0.5 each.

The partial pressure of the nitrogen in the mixture is equal to the product of mole fraction of nitrogen and total pressure.

It is 0.5×1=0.5 atm.

Answer 2

Given:

NO3 moles = 25

S02 moles = 100

Total moles = 125

Total pressure exerted (p)= 100

To Find:

Partial pressure of NO3 (P°)

Solution:

The formula for the partial pressure is,

${p}^{o} = p \times mole \: fraction$

where,

P° is the partial pressure of NO3,

P is the total pressure,

and mole fraction refers to the number of moles of NO3 divided by total number of moles.

Therefore, mole fraction of NO3 is

$mole fraction = \frac{25}{125} = \frac{1}{5}$

Now, putting the values in the above equation we get,

${p}^{o} = 100 \times \frac{1}{5}$

${p}^{o} = 20 \: atm$

Hence, the partial pressure of NO3 is 20 atm.