For a multielectron atom, which among the following orbital has maximum energy?
a) 5f
b) 3d
c) 4s
d) 2p
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Answer:
a) 5f
The orbital energies are compared with the help of n+l rule. The higher value of n+l, higher is the energy of the orbital.
5d=n+l=7
5f=n+l=8
6s=n+l=6
6p=n+l=7
The n+l value is greatest for 5f orbital.
Hence it has the highest energy among the given options.
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