Question

For a MX2 type salt if Ksp is solubility product then solubility is

Answer 1

Given:

$K_{sp}$  of M$X_2$ salt = Solubility of the product

Solution:

Dissociation of salt yields

$MX_2\rightarrow M^+ +2X^-$

According to the given data,

K_{sp} = solubility of the product

Consider $M^+$ = S and $2X^-$ = 2S

∴ $K_{sp}$ = $s\times (2s)^2$

$K_{sp}$ = s × 4$s^2$

$K_{sp}$ = $4s^3$

As solubility is to be calculated

$4s^3 = K_{sp}$

$s^3 = \frac{K_{sp}}{4}$

s = $\sqrt[3]{\frac{K_{sp}}{4} }$

This for the given type of salt if $K_{sp}$ is solubility product then solubility is  $\sqrt[3]{\frac{K_{sp}}{4} }$.

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Answer 2

Explanation:

hope this will help you